Question

15 cot A = 8 ಆದರೆ sinA ಮತ್ತು SecA
ಕಂಡುಹಿಡಿಯಿರಿ.​

Answer 1

Answer:

15 cot A = 8

Then,

cot A = 8/5

= tan A = 15/8 -----------( tan A = 1/cotA)

We know that

tan0 = opposite side / adjacent side

consider the attached figure , triangle ABC From Pythagoras theorem AC square = AB square + BC square

AC square = 8 square + 15 square = 64 + 225 = 289

AC = 17

cos A = ajacent sid / Hypotenus = AB /AC = 8/17

SecA = 1/cos A = 1/8 /17 Or 17/8

sin A = opposite side / hypotenus = BC / AC = 15/17