15 cylindrical pillars of a building have to be cleaned if the diameter of which village 42 centimetre and the height of a spinner is 5 M ,what will be the cost of cleaning these pillars at rate of rs 10 per square meter.
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The total number of cylindrical pillars = 15.
Given height = 5m.
Given that Diameter of the pillar = 42 centimeters.
Then the radius will be r = d/2 = 21cm.
We know that curved surface area = 2pirh
= 2 * 22/7 * 21 * 5
= 2 * 22 * 3 * 5
= 660.
If the cost of 1 cylindrical pillar = 660.
Then the cost of 15 cylindrical pillars = 15 * 660
= 9900.
Given the cost of cleaning at the rate per square meter = 10.
Therefore the cost of cleaning the paint at the rate of 10 per sq.m
= 9900 * 10
= 99000.
Hope this helps!
Given height = 5m.
Given that Diameter of the pillar = 42 centimeters.
Then the radius will be r = d/2 = 21cm.
We know that curved surface area = 2pirh
= 2 * 22/7 * 21 * 5
= 2 * 22 * 3 * 5
= 660.
If the cost of 1 cylindrical pillar = 660.
Then the cost of 15 cylindrical pillars = 15 * 660
= 9900.
Given the cost of cleaning at the rate per square meter = 10.
Therefore the cost of cleaning the paint at the rate of 10 per sq.m
= 9900 * 10
= 99000.
Hope this helps!
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