15. Determine the greatest 2 digit number which is exactly divisible by 4,16 and 24
and 2
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Answer = 96
Solution:
Lowest among 3 digits number=100, which is divisible by 4 and quotient is 25. So largest 2 digit number divisible by 4 must have quotient 24, and the number is 24×4=96
For 6, 100/6 , quotient 16, remainder 4. Here the largest 2 digit number = 100–4=96
For ,8, 100/8, quotient 12, remainder again 4, in this case also largest 2 digit number divisible by 8 = 100–4=96
For 12, 100/12, quotient =8 , remainder again 4.Again largest 2 digit number divisible by 12= 100–4=96.
So largest 2 digit number divisible by 4, 6,8,12 is 96
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