Question

15
Electric field strength at position vector r= (4i+ 3j) m caused by point charge q =
5uC placed at origin is
A) 1440i + 1080 ; V/m
C) 1240i + 1280 ; N/C
B) 1440i + 1080 ) N/m
D) 1240i + 1080 % N/m​

Answer 1

Explanation:

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Answer 2

Answer:

The correct answer is B) 1440i + 1080 N/m.

Explanation:

What is Electric field strength?

Electric field strength is a physical quantity that describes the strength and direction of the electric field at a point in space. It is defined as the force per unit charge experienced by a test charge placed at that point in the electric field. The magnitude and direction of the electric field strength make it a vector quantity.

The electric field strength at a point in space is determined by the presence and distribution of electric charges in the surrounding space. The electric field strength can be calculated using Coulomb's law or Gauss's law, depending on the nature of the charge distribution.

Electric field strength is measured in units of newtons per coulomb (N/C) or volts per meter (V/m).

The electric field strength at a point in space caused by a point charge q is given by Coulomb's law:

E = (1/4πε₀) * (q/r²) * r̂

where ε₀ is the electric constant, q is the charge of the point charge, r is the distance between the point charge and the point where the electric field is being calculated, and r̂ is the unit vector pointing from the point charge to the point in space.

In this case, the distance between the point charge and the point where the electric field is being calculated is:

r = √[(4-0)² + (3-0)²] = 5 m

The unit vector pointing from the point charge to the point in space is:

r̂ = (4i + 3j)/5

Substituting the values of q, r, and r̂ in Coulomb's law, we get:

E = (1/4πε₀) * (5×10⁻⁶ C/25 m²) * (4i + 3j)/5 E = (9×10⁹ N·m²/C²) * (1/5) * (4i + 3j)/5 E = (1440i + 1080j) N/C

Therefore, the electric field strength at position vector r= (4i+ 3j) m caused by point charge q = 5uC placed at origin is 1440i + 1080 N/m.

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