Math, asked by kushaldhoot707, 6 months ago

15. Evaluate using the formula:
(i) 79³ + 3(79)² + 3(79) + 1
(ii) 48³ + 6(48)² + 12 (48) + 8
please using formula onlyline by line explaination​

Answers

Answered by lakshmigangadhar1986
5

Answer:

I) (79+1)^3= 80^3. ii) (48+2)^3=50^3

Step-by-step explanation:

(A+B) ^3=A^3+3A^2B+3AB^2+B^3

therefore, 79^3+3(79)^2+3(79)+1

=79^3+3(79)^2×1+3(79)(1)^2+1^3

=(79+1)^3=80^3. [A=79,B=1]

ii) 48^3+6(48)^2+12(48)+8

=48^3+3(48)^2×2+3(48)(2)^2+2^3

=(48+2)^3=50^3. [A=48,B=2]

Answered by aarohis798
1

Answer:

by a simple formul..❣️❣️

Step-by-step explanation:

hope it help..

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