Math, asked by aron85, 11 months ago

15) Factorise: a) 14m - 21 b) 4a2

- 9 c) x2 + 10x + 25 d) x2

- 9x + 20​

Answers

Answered by Anonymous
2

\huge\underline\mathcal{Answer}

a). 14m-21

14m = 21

m = 21/14

m= 3/2

______________________

b). 4a²-9

4a² = 9

a² = 9/4

a = ±√(9/4)

a = ±3/2

______________________

c). x²+10x+25

x²+5x+5x+25=0

x(x+5)+5(x+5)=0

(x+5)(x+5)=0

x=-5

_________________________

d). x²-9x+20

x²-4x-5x+20=0

x(x-4)-5(x-4)=0

(x-5)(x-4)=0

x=4 and 5

_________________________

Answered by tz39263
0

Answer:

a) 14m-21

7(2m-3)

b) ( it cant be done since its 4a2 which isnt possible as far as i know)

c)  ( there is no common factor but u could do this)

2(x+5x)5(0+5)

d) x2-9x+20 ( again no common factor)

x(2-9)5(0+4)

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