Question

15. Factorise a4x2 - 2a3x + a2
(1) (a2x - 1)(ax - 1)
(3) a2(ax - 1)(ax - 1)
(2) (ax - 1)(ax - 1)
(4) a2(1 - ax)(a - 1)​

Answer 1

$\underline{\textbf{Given:}}$

$\mathsf{a^4x^2-2a^3x+a^2}$

$\underline{\textbf{To find:}}$

$\mathsf{Factors\;of\;a^4x^2-2a^3x+a^2}$

$\underline{\textbf{Solution:}}$

$\mathsf{consider,}$

$\mathsf{a^4x^2-2a^3x+a^2}$

$\mathsf{Taking\;a^2\;as\;common}$

$\mathsf{=a^2\left[a^2x^2-2ax+1\right]}$

$\mathsf{=a^2\left[a^2x^2-ax-ax+1\right]}$

$\mathsf{=a^2\left[ax(ax-1)-1(ax-1)\right]}$

$\mathsf{=a^2\left[(ax-1)(ax-1)\right]}$

$\implies\boxed{\mathsf{a^4x^2-2a^3x+a^2=a^2(ax-1)(ax-1)}}$

$\underline{\textbf{Answer:}}$

$\textsf{option (3) is correct}$

$\underline{\textbf{Find more:}}$

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Answer 2

Answer:

option c is correct

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