15. Find the area of the
Traingle whose vertices are
(5,4) (3,8) &(-2,10)
Answers
Answered by
2
Step-by-step explanation:
Let A(5,4)=X¹,Y¹ B(3,8)=X²,Y² andC(-2,10)=X³,Y³
Area of triangle ABC=1/2(x¹(y²-y³)+x²(y³-y¹)+x³(y¹-y²))
1/2(5(8-10)+3(10-4)+(-2)(4-8))
1/2(5(-2)+3(6)-2(-4)
1/2(-10+18+8)
1/2(-10+26)
1/2(16)
8 square units
Answered by
47
Given:-
Vertices of triangle are as follows:-
- (5, 4)
- (3, 8)
- (-2, 10)
To Find:-
- Area of the triangle.
Solution:-
We are given with three points (or vertices) of the triangle i.e. (5, 4), (3, 8) and (-2, 10)
From here we get the following:-
We already know:-
Putting all the values in the formula:-
∴ The area of the triangle is 8 square units.
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Learn More!!!
↦ What are x₁, x₂, x₃, y₁, y₂ and y₃?
- x₁ is the abscissa of the first point given i.e. (5, 4)
- x₂ is the abscissa of the second point given i.e. (3, 8)
- x₃ is the abscissa of the third point given i.e. (-2, 10)
- y₁ is the ordinate of the first point i.e. (5, 4)
- y₂ is the ordinate of the second point i.e. (3, 8)
- y₃ is the ordinate of the third point i.e. (5, 4)
NOTE:- The highlighted words represent abscissa and ordinate of the respective points.
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