15. Find the area of triangle whose vertices are (2, 3), (– 1, 0) and (2, – 4).
Answers
Answered by
11
Answer :
- Area of the triangle is 10.5cm².
Given :
- Vertices of a triangle are (2 , 3), (-1 , 0), (2 , -4).
To Find :
- Area of the triangle.
Solution :
Let
ABC be the triangle in which
- A = (2 , 3)
- B = (-1 , 0)
- C = (2 , -4)
Here
- x1 = 2
- x2 = -1
- x3 = 2
- y1 = 3
- y2 = 0
- y3 = -4
As we know that
Area of a triangle is
- ½ [x1 (y2 - y3) + x2 (y3 - y1) + x3 (y1 - y2)
Put the values in the formula
Now,
According to question :
→ 1/2 [ 2 {0 - (-4)} + (-1) {(-4) - 3} + 2 {3 - 0) ]
→ 1/2 [ 2 × 4 + (-1) × (-7) + 2 × 3 ]
→ 1/2 [ 8 + 7 + 6 ]
→ 1/2 × 21
→ 21/2
→ 10.5cm²
Hence, the area of the triangle is 10.5cm².
Answered by
27
Given
- Vertices of a triangle are (2,3), (-1,0) and (2,-4).
⠀
To find
- Area of the given triangle.
⠀
Solution
- We have three vertices of the triangle. Now, we have to find the area of the triangle.
⠀
⠀⠀⠀⠀❍ We know that
⠀
Here
⠀
★ Putting the values
⠀
⠀
⠀
⠀
⠀
⠀
Hence,
- The area of the triangle is
square units.
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