Question

15.
Find the equivalent resistance of the circuit.

(1) 10 Ω
(2) 16Ω
(3) 22 Ω
(4) 28 Ω​

Answer 1

Answer:

Hope it helps you !!!

But it is not in the option .

way of finding equivalent resistance if they are in series we just simply add them and if they are in parallel we add their reciprocals .

Answer 2

$\bold{\underline{\underline{ANSWER:}}}$

Equivalent resistance of the circuit is 16Ω.

$\bold{\underline{\underline{EXPLANATION:}}}$

In the fig, there are 2 resisters are in the Circuit Board & 2 resisters are out of circuit Board.

So, we will take resisters in the Circuit Board as in Series & resisters out of circuit Board as Parallel.

To find, Equivalent resistance Of the Circuit , we have to find the formulas of parallel and series resistance.

First, we will find parallel resistance.

         $\frac{1}{R} = \frac{1}{R_1}+\frac{1}{R_2}$

         $\frac{1}{R} = \frac{1}{15}+\frac{1}{1}$

         $\frac{1}{R} = \frac{1+15}{15}$

         $\frac{1}{R} = \frac{16}{15}$

         $\frac{1}{R} = \bold{1}$

Now, we will find resistance in Series.

         $\bold{R} = \bold{R_1}+\bold{R_2}$

         $\bold{R} = \bold{10}+\bold{5}$

         $\bold{R} = \bold{15}$

Now, to find equivalent resistance we will add their ans:

               equivalent resistance = parellel + series

                                                     = 15+1

                                                     = 16Ω.

Hence, the equivalent resistance is 16Ω.