Question

15 Find the solution for the pair of linear equations by any sutiable method 3x + 2y-7 = 0 4x+ y - 6=0​

Answer 1

Answer:

3x+2y=7

4x+y=6⇒y=6−4x

placing in equation (1)

3x+2(6−4x)=7

3x+12−8x=7⇒−5x+12=7

−5x=7−12⇒−5x=−5

x=1

∴ y = 6 - 4×1=2

∴ x = 1, y = 2

Answer 2

Answer:

x=1 ; y=2

Step-by-step explanation:

$\\ 3x+2y-7=0\\ 4x+y-6=0$

by elimination method:

$3x + 2y-7 = 0\\2 (4x+ y - 6=0)$

$3x + 2y-7 = 0\\8x+2y-6=0$

by eliminating 2y we get,

$-5x+5=0$

$-5x=-5\\x=1$

by substituting value of x in eqn (2)

$4x+y-6=0$

$4(1)+y-6=0\\4+y=6\\y=2$