Question

15. Find the square root of the following by factorization:
i) 196 ii) 256 iii) 1156​

Answer 1

Answer:

14

16

34

hope it helps

guys

Answer 2

Answer:

Step-by-step explanation:

1. 196

2 | 196

2 | 98

7 | 49

7 | 7

  |  1

$\sqrt{196} = \sqrt {2*2*7*7}=\sqrt{14*14}=14$

2. 256

2 | 256

2 | 128

2 | 64

2 | 32

2 | 16

2 | 8

2 | 4

2 | 2

  | 1

$\sqrt{256}=\sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2}\\=\sqrt{16 \times 16} = 16$

3. 1156

2  | 1156

2  | 578

17 | 289

17 | 17

   | 1

$\sqrt{1156} = \sqrt{2 \times 2 \times 17 \times 17}\\= \sqrt{34 \times 34} = 34$