Question

15. Find the sum of first hundred even natural numbers which are divisible
by 5.
​

Answer 1

Answer:

here a=5,d=5n=100

sn =n/2(2a+(n-1)d)

=50×10+495

=50×505

=25250

I hope this answers helpful to you

plz mark as brainlist

if you are followed my Ans

Answer 2

Answer:

Step-by-step explanation:

5,10,15,20.............500--------ap

a= 5

d= 5

An=500

An=a+(n-1)d

500=5+(n-1)5

500=5+5n-5

500=5n

n=500/5

n=100

Sn=n/2(2a+(n-1)d)

Sn=100/2(2×5+99(5)

Sn=50(10+495)

Sn=50(505)

Sn= 25250