Question

15) Find the value of :(3° + 4-1) * 2²​

Answer 1

Answer:

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${n}^{2} = 1$

${n}^{ - 1 } = \frac{1}{n}$

$\bold\red{Therefore, }$

$= ( {3}^{0} + {4}^{ - 1} ) \times {2}^{2}$

$= (1 + \frac{1}{4} ) \times 4$

$= ( \frac{4 + 1}{4} ) \times 4$

$= \frac{5}{4} \times 4$

$= 5 \: \: \: answer$