Question

15.From a point on the ground, 1 point
the top of a tree is seen to have
an angle of elevation 60°. The
distance between the tree and
a point is 50 m. Calculate the
height of the tree? *
67.2 m
56.8 m
O
66.6 m
86.6 m​

Answer 1

Refer to the attachment for diagram

In Δ ABC ,

$\tt \implies \tan(60) = \frac{AC}{50}$

$\tt \implies \sqrt{3} = \frac{AC}{50}$

$\tt \implies AC = \sqrt{3} \times 50$

$\tt \implies AC = 86.600 \: \: m$

The height of tree is 86.6 m

Remmember :

$\tt \star \: \: Sin (\theta ) = \frac{P}{H}$

$\tt \star \: \: Cos ( \theta) = \frac{B}{H}$

$\tt \star \: \: Tan( \theta) = \frac{P}{B}$