Question

15 g N2 reacts with 10 g H2 to produce NH3 . calculate the NH3 formed? identify the limiting agent?​

Answer 1

Answer:

Explanation:

The reaction is

N2 +3H2 gives 2NH3

We have 15 g of N2 so moles of N2=15/28=0.503= approx 0.5 moles

We have one N2 molecule so moles for each N2 is 0.5 moles

Similarly we have 10/2=5moles of H2 but we have 3 H2 atoms so moles for each H2 atom =5/3=1.67 moles of H2

Since moles of N2 is less than moles of H2, limiting reagent is N2

So moles of NH3 formed= 1/2 × 0.5=0.25 moles

So mass of NH3 = 0.25× 17=4.25g

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