15 g of ammonium chloride is dissolved in 250 ml of solution? Calculate the mass by volume percentage of solution
Answers
Answer:
Calculate the amount of ammonium chloride required to dissolve in 500mL ... Mass in g=0.9 ×53.5=48.15g ... Get Instant Solutions, 24x7.
Calculate the amount of ammonium chloride required to dissolve in 500mL water to have pH=4.5 (K
b
for NH
4
OH is 1.8×10
−5
)
[H
+
]=10
−pH
=10
−5
=3.162×10
−5
M
Let C be the concentration of NH
4
Cl
NH
4
+
+H
2
O⇌NH
4
OH+H
+
C(1−h) Ch Ch
If h is small then
K
h
=Ch
2
[K
h
=
K
a
K
w
=
1.8×10
−5
10
−14
=5.5×10
−10
]
h=
Ch
K
h
=
[H
+
]
K
h
=
3.162×10
−5
5.5×10
−10
=1.739×10
−5
C=
h
[H
+
]
=
1.739×10
−5
3.162×10
−5
=1.8molL
−1
500mL of water contains=
2
1.8
=0.9mol
Mass in g=0.9×53.5=48.15g
The pK
a
of CH3COOH and pK
b
of NH
4
OH is 4.76 and 4.75. respectively. Calculate the hydrolysis constant of ammonium acetate (CH
3
COONH
4
) at 298 K and also the degree of hydrolysis and pH of its
Calculate the pH of 1.0×10
−3
M sodium phenolate, NaOC
6
H
5
. K
a
for HOC
6
H
5
is 1.05×10
−10