Math, asked by ishitaneha13, 4 months ago

15
Given: P = {x|x = 15/a, aeN, XeN}, Q = yly=28/a,aeN, YeN
Find: PUQ. PUQ​

Answers

Answered by ravi2303kumar
2

Answer:

P∪Q = {1,2,3,4,5,7,14,15,28}

P∩Q = {1}

Step-by-step explanation:

P = {x | x = 15/a, a∈N, X∈N}  

 => P = {15/1 , 15/3, 15/5,15/15}

 => P = {15 , 5, 3,1}

 => P = {1,3,5,15}

Q = {y  ly=28/a, a∈N, Y∈N}

 => Q = {28/1,28/2,28/4,28/7,28/14,28/28}

 => Q = {28,14,7,4,2,1}

 => Q = {1,2,4,7,14,28}

=> P∪Q = {1,3,5,15} ∪ {1,2,4,7,14,28}  = {1,2,3,4,5,7,14,15,28}

=> P∩Q =  {1,3,5,15} ∩ {1,2,4,7,14,28} = {1}

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