Question

15. (i) A man bought two cows for Rs. 1030. By selling one of them at a gain of 10% and the other
at a loss of 4%, he got the same money in each case. Find the C.P. of each cow.​

Answer 1

Heya!

Let the price of the first cow be x and the second's be y.

Then, x + y = 1350

Also, given that in the whole transaction, the man neither gains nor losses which means, numerical value of the loss is equal to the numerical value of profit.

That is, 6% of x = 7.5% of y

or, x : y = 5 : 4

9 (5 + 4) = Rs. 1350 [Since total profit is Rs. 1350]

2nd cow's price = 4/9 × 1350 = 600 (answer)

5/9 × 1350 = Rs. 750 (1st cow) [5 represents the CP of the cow sold at 6% loss]

Hope it helps!!