Question

15. I have a total of 300 in coins of denomination 1, 2 and 5. The
number of 2 coins is 3 times the number of 5 coins. The total number of
coins is 160. How many coins of each denomination are with me?​

Answer 1

Step-by-step explanation:

let the no. of rs 5 coins be x

& the no. of rs 1 coin be y

& no. of rs 2 coins be 3 x

a.q.t total no. of coins = 160

x + 3x+y = 160

4x + y = 160 eq. 1

again a.q.t total rs = 300

5x + 2(3x) + 1y = 300

11x + y = 300 eq. 2

by elimination method

on subtracting both the equations

4x + y = 160

-11x -y = -300

=-7x =-140

x =20

on putting the the value of x in eq 2

4(20) + y =160

80 + y = 160

y =80

now,

no of rs 2 coins = 3(20)

= 60

no. of rs 5 coins = 20

no. of rs 1 coins=80

Answer 2

Hey mate !

Your answer is in the attachment .

No. of Re 1 coin - 80

No. of Rs 2 coins - 60

No. of Rs 5 coins - 20

Hope it helps !

❤️