Math, asked by debjoytiacharjee, 3 months ago


15. If a/b=b/c,
prove that (a+b+c)(a - b+c) = (a2 + b2 + c2).



[Hint. Let a/b=b/c= k. Then, b = ck and a = bk.

therefore, b = ck and a = ck2.
Put these values in required identity and show that L.H.S. = R.H.S.]​

Answers

Answered by milan8725
0

Answer:

To Prove : (a+b+c)(a−b+c)=a

2

+b

2

+c

2

Proof : a,b,c are in continued proportion.

b

a

=

c

b

=k (let)

b=ck

a=bk=(ck)k =ck

2

L.H.S. =(ck

2

+ck+c)(ck

2

−ck+c)

=c

2

(k

2

+k+1)(k

2

−k+1)

=c

2

[(k

2

+1)

2

−(k)

2

]

=c

2

[k

4

+2k

2

+1−k

2

]

=c

2

[k

4

+k

2

+1]

R.H.S. =c

2

k

4

+c

2

k

2

+c

2

=c

2

[k

4

+k

2

+1]

L.H.S = R.H.S.

Answered by Anonymous
2

Step-by-step explanation:

this is proved that left hand side = right hand side

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