Question

15. If a ball is thrown vertically upwards with speed 40
m/s, the distance covered during the last second of
its descent will be (g = 10 m/s2)
(1) 70 m
(2) 90 m
(3) 35 m
(4) 125 m​

Answer 1

Explanation:

Initial velocity (u) = 40 m/s

Acceleration

Time = 2 seconds

By Ist equation of motion,

v = u + at

v = 40 - 10 (2) =20 m/s

Answer 2

Answer:

4 is correct answer mark as brainlist