Question

15. If a box contains 3 red and 5 blue balls, find the probability of drawing one blue ball.
P to circle of radius A and centre​

Answer 1

A box contains 3 red balls and 5 blue balls.

We have to find the probability of drawing one of the blue balls.

We know that,

$\star \ \underline{\boxed{\sf P(E) = \dfrac{Favourable \ Outcomes}{Total \ Number \ Of \ Outcomes}}}$

Here,

Total no.of outcomes = No.of red balls + No.of blue balls = 8.

Thus,

$\longrightarrow \sf P(E) = \dfrac{5}{8} \\ \\ \longrightarrow \boxed{ \boxed{ \sf P(E) = 0.63}}$

Therefore, the probability of getting a blue ball is 0.63

Answer 2

Answer:

• Box contains 3 red and 5 blue balls
• Find probability of drawing one blue ball

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\Longrightarrow\sf P(E) = \dfrac{Favourable \ Outcomes}{Total \ Number \ Of \ Outcomes}\\\\\\:\Longrightarrow\sf P(E) = \dfrac{Blue \ Balls}{Red \ Balls+Blue \ Balls}\\\\\\:\Longrightarrow\sf P(E) = \dfrac{5}{3 + 5}\\\\\\:\Longrightarrow\sf P(E) = \dfrac{5}{8}\\\\\\:\Longrightarrow\sf P(E) = 0.625$

⠀

$\therefore\:\underline{\textsf{Probability of drawing one blue ball is \textbf{0.625}}}.$