Question

15. If both the zeroes of the quadratic polynomial
p(x) = (k+2) -(-2) - 5 are equal in magnitude
but opposite in sign, then find the value of k.
​

Answer 1

Answer:

hey there ❤❤.

your answer is here ⤵❤

p(x)= -3k +(-6)

= k => 2

hope it's help you ✌

Answer 2

Correct Question

If both the zeroes of the quadratic polynomial

p(x) = (k+2)x² -(k -2)x - 5 are equal in magnitude

but opposite in sign, then find the value of k.

$\rule{200}2$

Answer

2

$\rule{200}2$

Explanation

Let the zeroes of given polynomial be $\sf\alpha$. Then, other zero would be $\sf -\alpha$

Now, we know that

sum of zeroes = $\sf -(\frac{coefficient\ of\ x}{coefficient\ of\ x^2})$

And, product of zeroes = $\sf -(\frac{constant\ term}{coefficient\ of\ x^2})$

Hence,

$\sf\alpha$ + ($\sf - \alpha$) = $\sf\frac{-(-(k - 2))}{(k + 2)}$

→ 0 = (k - 2)/(k + 2)

→ k - 2 = 0

→ k = 2