Physics, asked by tannu9380, 3 months ago

15. If density of a planet is double that of the earth
and the radius 1.5 times that of the earth, the
acceleration due to gravity on the surface of the
planet is
(1)3/4 times that on the surface of earth

2) 3 times that on the surface of the earth

(3) 6 times that on the surface of the earth

(4)4/3 times that on the surface of the earth​

Answers

Answered by altuphaltu7
0

Answer:

answer - (4) 4/3 Times that on the surface of the earth

Answered by yasharma245
1

Answer:

The correct option 2 is

We have ,

The density of the planet is double of the earth

So , Dp = 2De

The radius of the planet is equal to 1.5 times the radius of the earth

So , Rp = 1.5Re

Since , Dp =2De

Mp Me

_____ = 2 ×_____

4/3Π 4/3 4R³é

Mp = 2 × (1.5)³ Me

So

gp GMp

___ = ____

ge R²p

___________

GMe²

_____

Re

gp = 3ge

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