Question

15. If n(U) = 50, n(A) = 30, n(AnB) = 15, n((A U B)') = 10 then find (i) n(B), (ii) n(B - A).

Answer 1

Answer:

given,

n(U)=50

n(A)=30

n(AnB)=15

n(AUB)'=10

(i) n(B)

n(AUB)=n(A)+n(B)-n(AnB)

n(B)=n(AUB)-n(A)+n(AnB)

=50-30+15=35

Answer 2

Answer: (i)n(B)=35 ,(ii)n(B-A)=20

Step-by-step explanation:

Given,$n(U)=50, n(A)=30, n(A\cap B)=15, n(A\cup B)'=10$

$n(A\cup B)=n(A)+n(B)-n(A\cap B)\\\therefore n(B)=50-30+15=35$

$n(B-A)=n(B)-n(B\cap A)\\\Rightarrow n(B-A)=35-15\\\therefore n(B-A)=20$

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