Question

15. If PQRS is a rhombus such that ZPRS = 52°, then find the measure of ZSPR and ZPOR. S R 520 P Q​

Answer 1

$\large \tt \underline{\red{ \star \: solution : }}$

We know,

• Angles of rhombus = 90°

$\large \sf \implies \: \angle psr = 90 \degree$

In Triangle PSR

• By angle Sum Property

$\large \tt \implies \: \angle spr + 90 \degree + 52 \degree = 180 \degree \\ \\ \large \tt \implies \: \angle spr +142 \degree = 180 \degree \\ \\ \large \tt \implies \: \angle spr = 180 \degree - 14 2\degree \\ \\ \large \sf \underline{ \boxed{ \sf \therefore \: \angle spr = 38 \degree}}$

Since,

• sides of rhombus = 90°
• PSR = PQR

PQR = 90°