Question

15. If the line passing through (4, -3), (6,0) and the line passing through (a, 7) and the
origin are parallel, then find the value of 'a'.​

Answer 1

Answer:

Please see the attachment

Answer 2

The value of a is $\dfrac{14}{3}$.

Step-by-step explanation:

We know that , Slope of line passing through (a,b) and (c,d) =$\dfrac{d-b}{c-a}$

Slope of line passing through (4, -3) and  (6,0) =$\dfrac{-3-0}{4-6}=\dfrac{-3}{-2}=\dfrac{3}{2}$  .......(1)

Slope of line passing through (a, 7) and (0,0) = $\dfrac{7-0}{a-0}=\dfrac{7}{a}$            .......(2)

Since slope of parallel lines are equal , so from (1) and (2), we have

$\dfrac{7}{a}=\dfrac{3}{2}\\\\\Rightarrow\ a=\dfrac{14}{3}$

Hence, the value of a is $\dfrac{14}{3}$.

# Learn more:

If P(2,4), Q(0,3) ,R(3,6) and S(5,y) are vertices of the parallelogram PQRS then find the value of y?

https://brainly.in/question/6544741