Question

15) If the point (2,5) lies on the graph of the equation 3y = kx²+7x-5, find the value of k. *


2/3

3/2

0

5/2​

Answer 1

Step-by-step explanation:

$\sf \huge \underline \red{AnswEr:-}$

(2,5) is satisfy the equation 3y = kx²+7x-5 , so

• x = 2
• y = 3

$\bf \leadsto \green{3y = k {x}^{2} + 7x - 5}$

$\bf \leadsto \green{3(5) = 4k + 14 - 5}$

$\bf \leadsto \green{15 = 4k + 9}$

$\bf \leadsto \green{4k = 15 - 9}$

$\bf \leadsto \green{4k = 6}$

$\bf \leadsto \green{k = \frac{6}{4}}$

$\bf \leadsto \pink{k = \frac{3}{2} }$

So , option c is ur answer !!

Verification:

$\bf \leadsto \green{15 = 4 \left( \dfrac{3}{2} \right) + 9}$

$\bf \leadsto \green{15 = 6 + 9}$

$\bf \leadsto \green{15 = 15}$

Hence Verified!!

Answer 2

Answer:

Sameer ke piche bahot h leken sameer aap ke piche h