Question

15) If the point (2,5) lies on the graph of the equation 3y = kx²+7x-5, find the value of k. *


2/3

3/2

0

5/2​

Answer 1

Answer:

thus answer is this

Step-by-step explanation:

As * (2k - 3, k + 2) lies on the line 2x + 3y + 15 = 0 So, putting x = 2k - 3 and y = k + 2 in equation, we get Rightarrow 2(2k - 3) + 3(k + 2) + 15 = 0 4k - 6 + 3k + 6 + 15 = 0 7k + 15 = 0 7k = epsilon-15 Rightarrow k=- 15 7