Question

15. If the radius of a sphere is halved then what is the decrease in its surface area?​

Answer 1

If the radius of the sphere is halved, what will be the change in its surface area?

ans>. Let radius of sphere be

Let radius of sphere be ′

Let radius of sphere be ′ r

Let radius of sphere be ′ r ′

Let radius of sphere be ′ r ′ then

Let radius of sphere be ′ r ′ thenSA=4πr

Let radius of sphere be ′ r ′ thenSA=4πr 2

Let radius of sphere be ′ r ′ thenSA=4πr 2

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, then

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π(

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r )

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 =

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 4

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2 =

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2 = 4

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2 = 41

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2 = 41

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2 = 41 × old surface area

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2 = 41 × old surface area∴

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2 = 41 × old surface area∴ 4

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2 = 41 × old surface area∴ 41

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2 = 41 × old surface area∴ 41

Let radius of sphere be ′ r ′ thenSA=4πr 2 If radius is halved, thenSA=4π( 2r ) 2 = 41 ×4πr 2 = 41 × old surface area∴ 41 th change is surface area.