Question

15) If the zero of the polynomial f(x) =x-3x+x+1 are (a-b), a
and (a+be​

Answer 1

Step-by-step explanation:

a−b,a,a+b are zeroes of x3−3x2+x+1

⇒a−b+a+a+b= sum of zeroes = 3

⇒3a=3

⇒a=1

(a−b)(a)(a+b)= product of zeroes =−1

⇒(1−b)(1+b)=−1

⇒1−b2=−1

⇒b2=2

⇒b=±2

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