Question

15. If the zeros of quadratic polynomial x'+la+1)x+b are 2 and -3, then find
a and b.
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Answer 1

Step-by-step explanation:

1st method

sum of zeroes =( -cofficient of x /cofficient of x ^ 2)

2= -(-b)/a

b=2

a=1

product of zeroes =(constant term / cofficient of x^2)

-3 = (c/a)

c= (-3)

a = 1

we all know the quadratic form is ax^2+bx+c

x^2+2x-3

2nd method

x^2 -(sum of zeroes )x+product of zeroes

x^2 -(2)x+(-3)

x^2-2x-3

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Answer 2

Answer:

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