Question

(15) If x= 2 + under root2 + under root 3 and y = 3 - under root 2 + under root3, prove that x2 + y2 – 4 x - 6 y + 3 = 0.​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

x=2+√2+√3

x²=(2+√2+√3)²

=4+2+3+4√2+2√6+4√3

=9+4√2+2√6+4√3

y=3-√2+√3

y²=(3-√2+√3)²

=9+2+3-6√2-2√6+6√3

=14--6√2-2√6+6√3

Now :

x²+y²-4x-6y+3

=9+4√2+2√6+4√3+14-6√2-2√6+6√3-8-4√2

-4√3-18+6√2-6√3+3

=0

proved