Question

15. If x48y is exactly divisible by 9, then find the least value of (x+y)?​

Answer 1

Answer:

so the devisibilty test of 9 says that the sum of all digits should be devisible by 9 so accordingly

x+4+8+y=devisible by 9

12+(x+y) = devisible by 9

closest no. devisible by 9 after 12 is 18 so

12+(x+y)=18

x+y=6

Answer 2

Answer:

The least value of (x+y) to be divisible by 9 is 6

Step-by-step explanation:

Divisibility by 9

For any number to be divisible by 9, the sum of the digits of the number has to be  divisible by 9.

Thus, for the given question,

x48y will be divisible by 9 if

(x+4+8+y)= a number divisible by 9.

⇒ (4+8)= 12,

and 12 is not divisible by 9.

However, the closest number to 12 divisible by 9 is 18.

Therefore , since we need the least value , we consider,

12+ (x+y)= 18

⇒ (x+y)= 18-12

⇒x+y = 6

Thus the least value of (x+y)  will be 6.