Physics, asked by khodifadvipul21, 7 months ago

15 in a bridge type full wave rectifier, if Vm is the peak voltage across the secondary of the transformer ,the maximum voltage coming across each reverse-biased diode is

A.2Vm
B. Vm/√2
C. A.Vm
D. 1/2 X​

Answers

Answered by sreeramavidya
8

Answer:

Ron H. The square root of 2 times the capacitance times the Ripple voltage (peak to peak) times the frequency equals the load current. and the frequency is 120 for a full wave rectifier.

Answered by amikkr
5

The correct answer to the above question is (a) which is 2Vm.

  • For rectifiers, Peak inverse voltage(PIV) or peak reverse voltage(PRV) can be defined as the maximum value of the reverse voltage of a diode, which occurs at the peak of the input cycle when the diode is in reverse bias.
  • A full-wave rectifier is defined as a rectifier that converts the complete cycle of alternating current into pulsating direct current (DC).
  • If Vm is the peak voltage across the secondary transformer, the maximum voltage coming across the reverse-biased diode is 2Vm.
  • In reverse biased p-n junction diode, the free electrons begin their journey at the negative terminal whereas holes begin their journey at the positive terminal.

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