Question

15. In a factory, 493056 clips were packed in 384 boxes. How many clips will be packed in 495 boxes
16 Find the product of the greatest and the smallest 3-digit numbers-formed with the digits 6,3 and 8.​

Answer 1

Answer:

493056/384=1284

495×1284=635580

Answer 2

$\begin {tabular} {|c|c|c| }</p><p>\cline {1-3} Number of clips(x) &493056&?\\</p><p>\cline {1-3} Number of boxes (y)&384&495 \\</p><p>\cline {1-3}</p><p>\end {tabular}$

$Number \: clips \: is \: increases \:number \:of \\boxes \: required \: increases$

$\therefore Number \:clips \: directly \:varies \\with \:the \: number \:of \:boxes \: packed$

$So, \frac{x_{1}}{y_{1}} = \frac{x_{2}}{y_{2}}$

$Here, x_{1} = 493056, \: x_{2} = \red{?}$

$y_{1} = 384 , \: y_{2} = 495$

$Substitute , \: \frac{493056}{384} =\frac{x_{2}}{495}$

$\implies x_{2} = \frac{493056\times 495}{384}$

$\implies x_{2} = 1284 \times 495$

$\implies x_{2} = 635580$

Therefore.,

$\red{ Number \:of \:clips \:be \:packed \:in }\\\red{ in \:495 \:boxes } \green {= 6,35,580 }$

__________________

$Given \: 3 \:digits \: 6,3 \:and \: 8$

$Heighest \:number \: formed \:by \: 6,3\\and\:8\: is \: \pink {863}$

$Smallest \:number \: formed \:by \: 6,3\\and\:8\: is \: \blue {368}$

/* According to the problem given */

$\red { The\: product \:of \:the\: greatest\: and}\\\red{ the\: smallest \:3-digit \:numbers-formed}\\\red{ with\: the\: digits\: 6,3 \:and \:8} \\= 863 \times 368 \\\green { = 3,17,584}$

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