Question

15) In an = 2n-1, then S2 is equal to
A) 2
B) 3
C) 4
D) 5​

Answer 1

Answer:

4

Step-by-step explanation:

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Answer 2

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$S_{2} = \frac{2}{2}(2a+(2-1)d)$

a + ( n - 1 ) d = 2n - 1

→ $\boxed{a = 3 - d }$

$S_{2} = 2(3-d)+d$

$S_{2} = 6-d$

Find the d yourself and put it in this you will get the answer