Question

15. In Figure. Bc and AMP and two right triangles.right angled at B
and M respectively prove that ABC ~ AMP​

Answer 1

In △ABC and △AMP,

∠ABC=∠AMP=90°

∠A is common.

∴ By AA criterion of similarity, △ABC ∼ △AMP

See figure also...

Answer 2

Answer:

In △ABC and △AMP,

In △ABC and △AMP,∠ABC=∠AMP=90

In △ABC and △AMP,∠ABC=∠AMP=90 o

In △ABC and △AMP,∠ABC=∠AMP=90 o

In △ABC and △AMP,∠ABC=∠AMP=90 o ∠A is common

In △ABC and △AMP,∠ABC=∠AMP=90 o ∠A is common∴ By AA criterion of similarity, △ABC ∼ △AMP