Question

15. In figure, find area of shaded region, where OB = 7 cm and OA = 14 cm, and ZAOC = 40°.
40°
B
С
A
D​

Answer 1

Answer:

g phone to be a good night to be a good night friends

Answer 2

Answer:

Given: Radius of inner circle =7 cm

Radius of outer circle =14 cm

Angle made by sector = 40o

Area of sector OAC = 360o40o×πr2

=91××722×142=68.44

Area of sector OBD = 360o40o×πr2

=91××722×72=17.11

Area of the small region ABDC 

= Area of the small sector OAC – Area of the small sector OBD =(68.44−17.11)cm2

Area of shaded region ABDC= Area of outer circle  −  Area of inner circle − area of small region ABCD

Area of shaded region ABDC=π×142−π×72−(68.44−17.11)cm2 Area of shaded region ABDC= Area of outer circle  −  Area of inner circle − area of small region ABCD

Area of shaded region ABDC=π×142−π×72−(68.44−17.11)cm2 

Area of shaded region ABDC=410.484 cm2