15. In the given circuit, the electric potential of P will be
(1) 5 V
(2) 6 V
(3) 8 V
(4) 9V
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Answer:
Electric potential at P will be 8 volt
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the electric potential of P will be 9 V
Explanation:
Charge across Each capacitor would be same as in Series
Q = CV
Hence
V₁ * 3 = V₂ * 1 = V₃ * 2
V₁ = 11 - P
Lets take Q potential between 1 & 2
V₂ = P - Q
(11 - P ) * 3 = (P - Q) * 1 = Q * 2
(P - Q) * 1 = Q * 2
=> P = 3Q
(11 - P ) * 3 = (P - Q) * 1
=> (11 - 3Q)3 = 3Q - Q
=> 33 - 9Q = 2Q
=> 11Q = 33
=> Q = 3
P = 3Q
=> P = 3*3 = 9
Hence the electric potential of P will be 9 V
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