15) In the given figure; 2C = 90° and D is mid-
point of AC. Find :
15
(i)
tan ZCAB
tan ZCDB
(ii)
tanZABC
tan ZDBC
D
B
do
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Answer:
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Step-by-step explanation:
In the given figure,
∠C=90
∘
In △ABC,
tan∠ABC=
B
P
=
BC
AC
In △CDB,
tan∠DBC=
B
P
=
BC
CD
Now,
tan∠DBC
tan∠ABC
=
BC
CD
BC
AC
tan∠DBC
tan∠ABC
=
CD
AC
tan∠DBC
tan∠ABC
=
CD
2CD
tan∠DBC
tan∠ABC
=2 (D is mid point of AC)
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