Question

15. In the given figure, AB CD. Prove that _BAE - ZECD = ZAEC. ​

Answer 1

Step-by-step explanation:

Produce BA to touch EC. Let the point of intersection be F.

Then,

∠AFE=∠ECD

Also, ∠BAE=∠AFE+∠AEC

Therefore,

∠BAE=∠ECD+∠AEC

∠BAE−∠ECD=∠AEC