Question

15 In the given figure, PQ is a diameter of a circle
with centre O. If PQR = 65°, SPR = 40°
and PQM = 50°, find QPR, QPM andPRS.​

Answer 1

It is given that: <PQR = 65°,<RPS = 40° , <PQM = 50°

<QRP = 90* (angle in a semi circle)

So,<QPR = 90° -  65° = 25°

PQRS  is a quadrilateral

So, <PSR = (180° - 65°)= 115°

<PRS = 180°– (115° + 40°) = 25°

<M = 90°,<QPM = 90°– 50°= 40°

I think it helps u..........