Question

15. In the given figure, PQ is a diameter of a circle
with centre O. If ZPQR = 65°, ZSPR = 40°
and ZPQM = 50°, find ZQPR, ZQPM and
ZPRS.

Answer 1

(i) ∠QPR=180° ∠PRQ−∠RQP

∠QPR = 180° - 90° - 65° = 25°

(ii) ∠QPM=180° ∠PMQ−∠PQM

∠QPM=180° −90° −50°=40

(iii) ∠PSR=180° −∠PQR

= 180° −65° =115°

∠PRS=180° ∠SPR−∠PSR

∠PRS=180° −40°−11° =15°

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