Question

15. In the given figure two triangles ABC and DBC lie on same side of BC such that PQ || BA and
PR || BD. Prove that QR || AD.
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Answer 1

Answer:

${ \to{ \sf{In \: triangle \: ABC}}}$,

AB||PQ

${ \to{ \sf{From \: BPT \: therom ,\: we \: know \: that \: \frac{cp}{bp} = \frac{cq}{aq} ......(1)}}}$

${ \to{ \sf{From \: BPT \: \frac{cp}{bp} = \frac{cr}{rd} .....(2)}}}$

${ \to{ \sf{From \: (1)and(2) \frac{cp}{bp} = \frac{cp}{bp} }}}$

By converse, of BPT QR||AD