Question

15. In this question A^B means A raised to the power B. If f(x) = ax^4 - bx^2 + x + 5 and f(-3) = 2, then f(3) =
a. 1
b. -2
c. 3
d. 8; 15. In this question A^B means A raised to the power B. If f(x) = ax^4 - bx^2 + x + 5 and f(-3) = 2, then f(3) =; a. 1; b. -2; c. 3; d. 8

Answer 1

here's your answer

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Answer 2

Answer:

$f(3) =8$  

Step-by-step explanation:

Given :$f(x) = ax^4 - bx^2 + x + 5$

To Find :  f(3)

Solution:

$f(x) = ax^4 - bx^2 + x + 5$

Substitute x = -3

$f(-3) = a(-3)^4 - b(-3)^2 + (-3) + 5$

$f(-3) = 81a - 9b -3 + 5$

$f(-3) = 81a - 9b +2$

we are given that f(-3)=2

So, $f(-3) = 81a - 9b +2 =2$

$f(-3) = 81a - 9b=0$ ---A

Substitute x = 3

$f(x) = ax^4 - bx^2 + x + 5$

$f(3) = a(3)^4 - b(3)^2 +3 + 5$

$f(3) =81a-9b+8$  

Using A

$f(3) =0+8$  

$f(3) =8$  

So, option D is true

Hence $f(3) =8$