Question

15. In triangle ABC, BD perpendicular AC. angle A = 45°, angle C = 30° and
BC = 20 cm. Find the length of (1) BD, (ii) AB.​ please answer this urgently.

Answer 1

Step-by-step explanation:

From,∆BDC

Sin30°=BD

BC

Or,1/2=BD/20 [BC=20Cm]

or,BD=20/2=10cm.........(1)[ANS]

NOW, For∆ABD

angle A=45°,angle D=90°

so angle B=180°-(45+90)

=45°

so AD=BD=10cm

AB=√(AD^2+BD^2)

AB=√100+100

AB=√200=10√2cm.............(2)[ANS]

Answer 2

Answer:

check the above picture

Step-by-step explanation:

the diagram is same just i drew it by my convince