Math, asked by devirashika854, 2 months ago

15 litres of a mixture contains alcohol and water
in the ratio 1:4. If 3 litres of water is mixed in it,
the percentage of alcohol in the new mixture will
be


Answers

Answered by Devil0987
1

Answer:

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Attachments:
Answered by ImperialGladiator
8

Answer:

→ 16⅔%

Step-by-step explanation:

Given ratio :

In a mixture of 15 litres the ratio of

→ Alcohol : Water

→ 1 : 4

Now, if 3 litres lf water is mixed in the mixture.

Find the % of alcohol in the new mixture.

Step 1 : Calculate the amount of water and alcohol :

If we assume the unit of ratio as “a”

We can say that,

→ 1a + 4a = 15 litres.

Or,

→ 5a = 15

→ a = 3 litres

Therefore, each unit is 3 litres.

So,

The amount of alcohol is 3 litres.

And also, the amount of water is 12 litres.

Step 2 : 3 litres of water adds up in the mixture :

The amount of water now will be :

→ 15 + 3 litres

18 litres.

Step 3 : Calculate the required % :

Required% is given by :

Amount of alcohol/New mixture × 100

→ 3/18 × 100

→ 1/6 × 100

→ 50/3

16⅔%

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