Math, asked by adityasharma000547, 6 months ago

15 litres of juice contains syrup and water in the ratio of 1:4. If more syrup is added until the ratio becomes 2:3, how many litres of juice is now available after the addition of syrup?

Answers

Answered by drgauravmishra1
3

Answer:

ATQ:-

1:4=15

1x:4x=15

sum of ratios = 5x

5x=15

x=3

syrup 3l

water 12l

now let x be the amount of syrup added

3+x/12=2/3

on solving

x=5

so syrup added =5 l

total = 12+3+5 = 20 litres is the correct one all above don,t know maths!!

Step-by-step explanation:

hope you understand

Answered by gayatrikumari99sl
0

Answer:

20 liters of juice is now available after addition of syrup.

Step-by-step explanation:

Explanation:

Given,

15 liters of juice contains syrup and water in the ratio of 1:4.

When more syrup is added, the ratio becomes 2:3

Let us assume that x liters of syrup is added to the juice.

Step1:

15 liters of juice contains syrup and water in the ratio of 1:4

Then the amount of syrup in the  juice =  (\frac{1}{1+4}) 15 liters

                                                                = \frac{15}{5}  = 3liters

And, the amount of water in the  juice = (\frac{4}{1+4}) 15 = \frac{4}{5}(15)

                                                                  = 12 liters

Now, when more syrup is added,

than the  total amount of syrup in the  juice

= (x+ 3) liters

Step2:

Now, when more syrup is added, the ratio of syrup to water becomes 2:3

Therefore , \frac{Amount of syrup }{Amount of water} = \frac{2}{3}

But we have the amount of syrup = (x+3) liters and

amount of water = 12 liters       (from step 1)

Now put the value in the above equation we get ,

\frac{x+3}{12} = \frac{2}{3}   ⇒ 3(x+3)= 12× 2

⇒ x + 3 = 8

⇒ x = 8 -3 = 5  

Step3:

There fore , the amount of syrup added to the juice = 5 liters

So , the total amount of juice now available after more syrup is added

 = 3 liters + 12 liters + 5 liters

= 20 liters

Final answer :

Hence , total 20 liters of juice is now available after addition of syrup.

#SPJ3

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